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Java 목록 sublist() 메서드

그만큼 하위 목록() 목록 인터페이스의 메소드는 포함 매개변수와 배타적 매개변수 사이에 있는 이 목록의 부분에 대한 보기를 반환합니다. 이 방법을 사용하면 명시적인 범위 작업이 필요하지 않습니다.

토폴로지

통사론

 public List subList(int fromIndex, int toIndex) 

매개변수

'fromIndex' 및 'toIndex' 매개변수는 하위 목록의 낮은 끝점과 높은 끝점을 나타냅니다.

반품

subList() 메소드는 이 목록 내에서 지정된 범위의 보기를 반환합니다.

던지기:

IndexOutOfBoundsException - 이 예외는 잘못된 엔드포인트 인덱스 값(예: fromIndex 크기 또는 fromIndex > toIndex)에 대해 발생합니다.

실시예 1

 import java.util.LinkedList; import java.util.List; public class JavaListSubListExample1 { public static void main(String[] args) { int fromIndex=2; int toIndex=7; List list= new LinkedList(); for (int i=1;i<=10;i++){ 2 7 list.add(i); } system.out.println('list : '+list); it will return the elements present from index to at list.sublist(fromindex,toindex); system.out.println('elements position '+list.sublist(2,7)); < pre> <span> Test it Now </span> <p> <strong>Output:</strong> </p> <pre> List : [1, 2, 3, 4, 5, 6, 7, 8, 9, 10] Elements from 2 index position to 7 index position : [3, 4, 5, 6, 7] </pre> <h2>Example 2</h2> <pre> import java.util.LinkedList; import java.util.List; public class JavaListSubListExample_2 { public static void main(String[] args) { List list= new LinkedList(); for (char ch=&apos;a&apos;;chtoIndex it will throw an exception System.out.println(&apos;List : &apos;+list.subList(18,12)); } } </pre> <span> Test it Now </span> <p> <strong>Output:</strong> </p> <pre> Total alphabets : 26 Exception in thread &apos;main&apos; java.lang.IllegalArgumentException: fromIndex(18) &gt;toIndex(12) atjava.util.SubList.(AbstractList.java:624) atjava.util.AbstractList.subList(AbstractList.java:484) at com.javaTpoint.JavaListSubListExample2.main(JavaListSubListExample2.java:12) </pre> <h2>Example 3</h2> <pre> import java.util.LinkedList; import java.util.List; public class JavaListSubListExample_3 { public static void main(String[] args) { List list= new LinkedList(); for (char ch=&apos;a&apos;;ch<='z';ch++){ list.add(ch); } system.out.println('total alphabets : '+list.size()); if fromindex<-1 || toindex< -1 it will throw an exception system.out.println('list '+list.sublist(-1,-1)); < pre> <span> Test it Now </span> <p> <strong>Output:</strong> </p> <pre> Total alphabets : 26 Exception in thread &apos;main&apos; java.lang.IndexOutOfBoundsException: fromIndex = -1 atjava.util.SubList.(AbstractList.java:620) atjava.util.AbstractList.subList(AbstractList.java:484) at com.javaTpoint.JavaListSubListExample3.main(JavaListSubListExample3.java:13) </pre></='z';ch++){></pre></=10;i++){>

실시예 2

 import java.util.LinkedList; import java.util.List; public class JavaListSubListExample_2 { public static void main(String[] args) { List list= new LinkedList(); for (char ch=&apos;a&apos;;chtoIndex it will throw an exception System.out.println(&apos;List : &apos;+list.subList(18,12)); } } 
지금 테스트해보세요

산출:

 Total alphabets : 26 Exception in thread &apos;main&apos; java.lang.IllegalArgumentException: fromIndex(18) &gt;toIndex(12) atjava.util.SubList.(AbstractList.java:624) atjava.util.AbstractList.subList(AbstractList.java:484) at com.javaTpoint.JavaListSubListExample2.main(JavaListSubListExample2.java:12) 

실시예 3

 import java.util.LinkedList; import java.util.List; public class JavaListSubListExample_3 { public static void main(String[] args) { List list= new LinkedList(); for (char ch=&apos;a&apos;;ch<=\'z\';ch++){ list.add(ch); } system.out.println(\'total alphabets : \'+list.size()); if fromindex<-1 || toindex< -1 it will throw an exception system.out.println(\'list \'+list.sublist(-1,-1)); < pre> <span> Test it Now </span> <p> <strong>Output:</strong> </p> <pre> Total alphabets : 26 Exception in thread &apos;main&apos; java.lang.IndexOutOfBoundsException: fromIndex = -1 atjava.util.SubList.(AbstractList.java:620) atjava.util.AbstractList.subList(AbstractList.java:484) at com.javaTpoint.JavaListSubListExample3.main(JavaListSubListExample3.java:13) </pre></=\'z\';ch++){>